Question

0.020 mol of glucose is dissoved in 200ml of water at 300K. Calculate the osmotic
pressure of the solution. (R=0.0821L.atm mol 'K')​

Answer 1

Answer:

The pressure is 2.463 atmosphere

Explanation:

PV=nRT

P= nRT/V

P= 0.020×0.0821×300/0.2

P= 2.463 atmosphere

Answer 2

osmotic  pressure of the solution is 2.4631 atm

• The osmotic pressure of a dilute solution is discovered to follow the same relationship as the ideal gas law

Given:

P(osmotic) = nRT/V

n = 0.020, R = 0.0821L.atm mol 'K', T = 300K, V= 200ml

To find:

Calculate the osmotic  pressure of the solution

Explanation:

P(osmotic) = nRT/V

P= 0.020 × 0.0821 × 300/ 0.2

P= 2.4631 atm

hence, osmotic  pressure of the solution IS 2.4631 atm