0.025 moles of glucose are desolved in 500ml aqueous solution at 20°c. What is the osmotic pressure of the solution?
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Answer:
Explanations:
moles = 0.025
volume = 0.5 litres
T = 293 K
moles = w/molecular weight
w= 0.025×180
w= 4.5 g
pi = W×RT/M V
pi = 0.0821×293×4.5/ 0.5×180
pi = 1.2 atm
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