Question

0.04 molal aqueous monoprotic acid has depression
in freezing point equal to 0.1 K then find vant Hoff
factor for acid :-
1200
(1) 1 (2) 2 (3) 2.5 (4) 1.34

Answer 1

Answer:

ΔT

f

=iK

f

m

where,

K

f

= Molal Freezing Point Depression Constant

i= Vant Hoff factor

m= molality of solution

∴ i=

K

f

m

ΔT

f

=

1.86×0.04

0.1

=1.34.

Thus, Vant Hoff factor is 1.34

Hence, the correct option is (4)