Question

0.05 moles of nahco3 will react with how many equivalent of mg(oh)2
a) 0.2 Eq.
b) 0.05 Eq.
c) 0.02 Eq
d) 0.01 Eq

Answer 1

0.05 moles of nahco3 will react with how many equivalent of mg (oh)2
b)0.02 Eq.

Answer 2

Answer: The correct answer is Option d.

Explanation:

We are given:

Moles of sodium bicarbonate = 0.05 moles

The balanced chemical equation for the reaction of sodium bicarbonate and magnesium hydroxide follows:

$2NaHCO_3+Mg(OH)_2\rightarrow Mg(HCO_3)_2+2NaOH$

By Stoichiometry of the reaction:

2 moles of sodium bicarbonate reacts with 1 mole of magnesium hydroxide.

Sp, 0.05 moles of sodium bicarbonate will react with = $\frac{1}{2}\times 0.05=0.025mol$ of magnesium hydroxide.

To calculate the number of equivalent of base, we use the equation:

$\text{Number of equivalents of base}=\frac{\text{Moles of base}}{\text{Acidity}}$

We are given:

Moles of magnesium hydroxide = 0.025 moles

Acidity of magnesium hydroxide = 2

Putting values in above equation, we get:

$\text{Number of equivalents of }Mg(OH)_2=\frac{0.025}{2}=0.0125$

Hence, the correct answer is option d.