Math, asked by kukusharma63, 10 months ago

(0.06)²+(0.47)²+(0.079)²/(0.006)²+(0.047)²+(0.0079)² =?​

Answers

Answered by veerendrakumaruppu
3
((0.06)^2 + (0.47)^2 + (0.079)^2)/((0.006)^2 + (0.047)^2 + (0.0079)^2)

= ((0.06)^2 + (0.47)^2 + (0.079)^2)/(((0.06)*(0.1))^2 + ((0.47)*(0.1))^2 + ((0.079)*(0.1))^2)

= ((0.06)^2 + (0.47)^2 + (0.079)^2)/(0.1)^2((0.06)^2 + (0.47)^2 + (0.079)^2)

= 1/(0.1)^2

= 1/0.01 ——> Answer
Answered by pinquancaro
6

\dfrac{(0.06)^2 + (0.47)^2 + (0.079)^2}{(0.006)^2 + (0.047)^2 + (0.0079)^2}=100

Step-by-step explanation:

Given : Expression \frac{(0.06)^2 + (0.47)^2 + (0.079)^2}{(0.006)^2 + (0.047)^2 + (0.0079)^2}.

To find : Solve the expression ?

Solution :

Solving the expression,

\dfrac{(0.06)^2 + (0.47)^2 + (0.079)^2}{(0.006)^2 + (0.047)^2 + (0.0079)^2}\\\\=\dfrac{(0.06)^2 + (0.47)^2 + (0.079)^2}{(0.06\times 0.1)^2 + (0.47\times 0.1)^2 + (0.079\times 0.1)^2}\\\\=\dfrac{(0.06)^2 + (0.47)^2 + (0.079)^2}{(0.06)^2\times (0.1)^2 + (0.47)^2\times (0.1)^2 + (0.079)^2\times (0.1)^2}\\\\=\dfrac{(0.06)^2 + (0.47)^2 + (0.079)^2}{(0.1)^2((0.06)^2 + (0.47)^2 + (0.079)^2)}\\\\=\dfrac{1}{(0.1)^2}\\\\=\dfrac{1}{0.01}\\\\=100

Therefore, \dfrac{(0.06)^2 + (0.47)^2 + (0.079)^2}{(0.006)^2 + (0.047)^2 + (0.0079)^2}=100

#Learn more

6. Simplify:

(a) 10 [330 – {25 – (22 – 15 – 13)}]​

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