0.0642 x 3.142
Find log & Antilog using log table
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Answer:
Given :
Heat gained = 4.5 × 10⁵ J
Heat released = 2 × 10⁵ J
To Find :
Percentage efficiency of steam engine and work done per cycle..
Solution :
❒ Efficiency of a heat engine/steam engine is given by, η = 1 - (Q₂ / Q₁)
Where,
η denotes efficiency
Q₂ denotes heat released to the sink
Q₁ denotes heat extracted from the source
By substituting the given values;
➛ η = 1 - (Q₂ / Q₁)
➛ η = 1 - (2 × 10⁵ / 4.5 × 10⁵)
➛ η = 1 - 0.44
➛ η = 0.56
Percentage efficiency = 56%
❒ Work done per cycle :
We know that work done is measured as the change in energy.
➠ W = Q₁ - Q₂
➠ W = (4.5 × 10⁵) - (2 × 10⁵)
➠ W = 2.5 × 10⁵ J
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