Question

0.085 kg of copper of specific heat capacity 100 cal kg! °C- and at
20°C is heated by a burner for one minute, which supplies heat energy
at a rate of 12 calories /sec. Calculate the final temperature of copper.​

Answer 1

Answer:

Explanation:

calories supplied in one minute = 12 x 60 = 720  calories

msΔt=calories

0.085 x 100 xΔt =720

Δt = 720x 1/100 x 1000/85

Δt will be 84.7°c

final temperature is 20°c + 84.7°c = 104.7°c

Answer 2

Answer:

104.7 °C

Explanation:

The total heat energy supplied in one minute will be

12 calories/second × 60 second = 720 calories

Now, according to the formula,

$Q=ms\Delta T\\\\\Delta T={Q\over ms}\\\\\Delta T={720\over 0.085\times 100}\\\\\Delta T=84.70~^{o}C$

If initial temperature is 20 °C, then final temperature will be

20 °C + ΔT = 104.7 °C.