Question

0.1. A cube of edge length 10 cm is placed inside a liquid. The pressure at the centre of the face is 15. Find the force exerted
by the liquid on this face. ​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Force (F)=0.15N }}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Edge Lenght (l) = 10cm or 0.1m

• Pressure (P) = 15Pa

$\large\underline\pink{\sf To\:Find: }$

• Force excreted (F) = ?

━━━━━━━━━━━━━━━━━━━━━━━━━

$\LARGE{♡}$$\large{\boxed{\sf Area\:of\:face(A)=(side)^2}}$

$\large\implies{\sf A=(0.1)^2 }$

$\Large\implies{\sf A=0.01m^2 }$

Force (F) :-

$\LARGE{♡}$$\large{\boxed{\sf Force(F)=P×A}}$

$\large\implies{\sf F=15×0.01 }$

$\large\implies{\sf F=0.15N }$

$\Huge\red{♡}$$\Large\red{\boxed{\sf Force (F)=0.15N }}$

Hence ,

Force exerted by the liquid on this face is 0.15N

Answer 2

$\huge{\boxed{\boxed{\mathfrak{\red{Answer:-}}}}}$

_____________________♥

$\huge\underline\orange{\sf Given:-}$

➡ Length of edge = 10cm =0.1m

➡Pressure = 15pa

$\huge\underline\orange{\sf To \: find:- }$

➡Force =❓

$\huge\underline\orange{\sf Solution:-}$

$\implies\ Area \: of \: Face(A)={0.1}^{2} \\ \\ \implies\ A = 0.01 \: {m}^{2}$

Now ,we know

$\implies\ Force= pressure \: X \: Area \\ \\ \implies\ F = 15 \: X \: 0.01 \\ \\ \implies\ F =0.15N$

Hence ,the force exerted was 0.15Newton .

$\huge\green{\boxed{\sf F = 0.15N}}$