Question

0.1. A particle moves 3m North, then 4m East and finally 6m South. Find the distance travelled and
the displacement.
of 30 km/h. How fast must

Answer 1

Explanation:

The particle travels from a to b to c to finally, d. The displacement will be the distance from initial to final points or, from a to d.

Thus, in triangle aa'd by using pythagoras theorem

ad^2 = 3^2 +4^2 = 25

thus, displacement, ad = 5 m

the total distance travelled will be equal to ab + bc + cd = 3m + 4m + 6m

or

distance = 13 m