Question

0.1.
Find the roots of the following equations by factorization method:
a
3x² - 2 √6 x+2=0​

Answer 1

${3x}^{2} - 2 \sqrt{6} x + 2$

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$3 \times 2 = 6 \\ 6 = - \sqrt{6} - \sqrt{6} \\ - \sqrt{6} - \sqrt{6} = - 2 \sqrt{6}$

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thus,

$3 {x}^{2} - 2 \sqrt{6} x + 2 \\ = {3x}^{2} - \sqrt{6}x - \sqrt{6}x + 2$

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$x = \frac{ \sqrt{6} }{3}$

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