Question

0.1 find the roots of the quadratic equation
6x^2-x-2=0​

Answer 1

Answer:

$6 {x}^{2} - x - 2 = 0 \\ 6 {x}^{2} - 4x + 3x - 2 = 0 \\ 2x(3x - 2) + 1(3x - 2) = 0 \\ (3x - 2)(2x + 1) = 0 \\ 3x - 2 = 0 \: \: \: or \: \: \: 2x + 1 = 0 \\ 3x = 2 \: \: \: or \: \: \: 2x = - 1 \\ \large{ \boxed{x = \underline{ \underline{ \frac{2}{3} }} \: \: \: or \: \: \: x = \underline{ \underline{ \frac{ - 1}{2} }}}}$