Question

0.1 g of calcium carbonate calculate the number of particle of calcium and oxygen​

Answer 1

Answer:

The molecular weight of calcium carbonate is 100 g per mole.

1 g of calcium carbonate corresponds to 0.01 mole.

1 molecule of calcium carbonate contains three oxygen atoms.

Thus, 0.01 mole of calcium carbonate will contain 0.03 moles of oxygen atoms which is equal to 0.03×6.02×10

23

=1.8×10

22

oxygen atoms.