Question

0 .1
If the nth term of a progression is (4n-10) show that it is an AP. Find its
(i) first term. (ii) common difference, and (iii) 16th term.​

Answer 1

Answer:

1st term = 4×1-10=-6

2nd term=4×2-10=-2

common difference=-2+6=4

16th term=4×16-10=64-10=54

Answer 2

Answer:

4n-10

Its first term will be n=1

4-10=-6

Its second term will be n=2

8-10=-2

It's third term will be n=3

12-10=2

Common difference

-2-(-6)=-2+6=4

2-(-2)=2+2=4

Therefore common difference is 4

16 term

an=a+(n-1)d

=-6+(16-1)4

=-6+60=54