Question

0.1 M hcl of 100 ml is mixed with 0.01 M of NaOh of 50 ml . calculate the pH of solution after mixing
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Answer 1

The correct question should contain 0.1 M, 50 ml NaOH

Heya,

No. of moles of H+ given by HCl = 0.1 × 100 = 10 millimoles

No. of miles of OH- given by NaOH = 0.1 × 50 = 5 millimole

Hence, volume of H+ remaining after neutralisation = 5 millimole.

Total volume = 100 + 50 = 150 ml.

Molarity of H+ = no. of moles/volume = 5/150 = 1/30

Hence,

pH = -log(H+) = -log(1/30) = 1.52287874528