0.1 M KI and 0.2 AgNO3 are mixed in 3:1 volume ratio. Find the depression in freezing point of the resulting solution. (By assuming Kf H2O=2Kkg/mol)
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Answer:
KI(aq)+AgNO
3
(aq)+KNO
3
(aq)
KI+AgNO
3
→KNO
3
+AgI
Initial : 0.3 mole 0.2 mole - -
Final : 0.1 mole - 0.2 0.2
Total moles of solute ions =(0.1+0.2)×2(∵i=2)
[Solute] =
4
0.6
M
ΔT
f
=K
f
4
0.6
=1.86×
4
0.6
=0.279K
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