0.1 mol of Na3Po4 completely dissociates in water to provideNa+
Answers
Answer:
The thing to keep in mind about osmolarity is that it takes into account the number of moles of particles of solute that are produced in a solution when a given number of moles of solute are dissolved to make said solution.
In other words, you can think about osmolarity as being a multiple of molarity
osmolarity
=
i
×
molarity
−−−−−−−−−−−−−−−−−−−−−−−
Here
i
represents the van't Hoff factor, which tells you the ratio that exists between the number of moles of particles of solute produced in solution and the number of moles of solute dissolved in solution.
In your case, trisodium phosphate is a strong electrolyte, which implies that it dissociates completely in aqueous solution to produce sodium cations and phosphate anions
Na
3
PO
4
(
a
q
)
→
3
Na
+
(
a
q
)
+
PO
−
4
(
a
q
)
Now, notice that every mole of trisodium phosphate that dissociates in solution produces a total of
3 moles Na
+
+
1 mole PO
−
4
=
4 moles ions
The number of moles of particles of solute produced in solution are actually called osmoles.
As a result, the van't Hoff factor will be equal to
i
=
4 moles ions produced (osmoles)
1 mole Na
3
PO
4
.
dissolved
=
4
Since you know that
[
Na
3
PO
4
]
=
2.0
⋅
10
−
3
M
you can say that the solution will have an osmolarity equal to
osmolarity
=
4
×
2.0
⋅
10
−
3
M
=
8.0
⋅
10
−
3
.
osmol L
−
1
−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
It's important to keep in mind that osmolarity is expressed in osmoles per liter because you have
2.0
⋅
10
−
3
moles Na
3
PO
4
1 L solution
⋅
4 osmoles
1
mole Na
3
PO
4
=
8.0
⋅
10
−
3
.
osmol L
−
1
Explanation:
Answer:
1.806by10power23
Explanation: