Question

0.1 mole of aqua solution of MgCl2 at 300k is 4.92 ATM what will be the percentage ionization of salt ​

Answer 1

Answer:

49%

Explanation:

a.π=iCRT

4.92=i×0.1×0.0821×300

i=1.99

α=i−1n−1=1.99−13−1=0.992=0.49