Question

0.1 mole of KMnO4 present in 500 ml solution got converted into K MnO4. The concentration of KMnO, is
a) 0.2 M
b) 0.2 N
c) 1 N
d) 0.04 N
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Answer 1

Answer:

a,b

Explanation:

+1 +1

KMnO4= K2MnO4

equalivant of KMnO4 is 1×2-1=1

molarity =milli moles/volume (ml)

moles given 0.1 = 0.1×10^3

volume given 500 ml

molarity=0.1×10^3/500

=0.2//

normality=meq/volume (ml)

meq=0.1/1 ×10^3

normality=0.1×10^3/500

=0.2//

I hoped it helped u...