Question

0.1 moles of a hydrocarbon on complete combustion produces 17.6 grams of C02. find the hydrocarbon. PLEASE DON'T SPAM OR I WILL DEFINITELY REPORT YOU. t's urgent please.

Answer 1

Answer:

$C_{4} H_{10\\}$

Explanation:

CnH2n+2 -----> n C02 (Combusion)

Given that

-> mole-0.1 ( CnH2n+2)

->

 CO2 1mole=44gr

 so, 17.6gr=0.4mole

->

 0.1 mole = 0.4mole

  CnH2n+2 -----> n CO2

1  CnH2n+2 -----> 4 CO2

  so, n =4

-> so, molecular formula is $C_{4} H_{10\\}$

Hope it helps you.

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