Question

0,1 - Which of the following are the roots of the equation x2- 2x +1=1​

Answer 1

Answer:

math]x^2-2x+1 = 0 [/math]

[math]\implies (x)^2 - (2×x×1) + (1)^2 = 0[/math]

[math]\implies (x-1)^2 = 0[/math]

[math][\because a^2-2ab+b^2 = (a-b)^2][/math]

[math]\implies (x-1)(x-1)=0[/math]

[math]\implies x = 1,1[/math]

Answer 2

Step-by-step explanation:

$x {}^{2} - 2x + 1 = 1 \\ x {}^{2} - 2x + 1 - 1 = 0 \\x {}^{2} - 2x = 0$