Question

0.10
1 point
p(x) = x2-27 के शून्यक हैं
:​

Answer 1

Given : p(x) = x²-27  

To Find :  शून्यक

Solution:

p(x) = x²-27  

p(x) = 0

=> x²-27   = 0

=> x² = 27

=> x  = ± 3√3

p(x) = x²-27    के शून्यक हैं  ± 3√3  

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