Physics, asked by shreegaming168, 5 hours ago

0 10 A 1.0 kW kettle contains 500 g of boiling water Calculate the time needed to evaporate all the water in the kettle. (Specific latent heat of vaporization of water = 2.26 MJkg-'). (3] Ans: 1.13x100 sec, negative b. Obtain a strength in Fig. 6 Edo lain why the

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Answered by sabitasingh76142

Explanation:

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Answered by knjroopa

Explanation:

Given A 1.0 kW kettle contains 500 g of boiling water Calculate the time needed to evaporate all the water in the kettle

So we need to find the time required to evaporate all the water in the kettle.
Now boiling point of water is 100 deg C.
So the heat required to boil water up to 100 deg C is
heat = mass x specific latent heat x temperature
= 500 x 2.26 x 100
= 113000 J
So power of kettle is 1.0 KW
P = 1 KW = 1000 W
So Power = Energy / time
1000 = 113000 / t
Or t = 113000 / 1000
t = 113 sec
Therefore the time needed to evaporate all the water in the kettle is 113 secs

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