0=100+2(-0.5) x s
find the value of s
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Answer:
For a first order reaction, we have:
k=
t
2.303
log
2P
o
−P
t
P
o
k=
100
2.303
log
2×0.5−0.6
0.5
k=2.23×10
−23
/s
Rate =kP
SO
2
Cl
2
The total pressure is 0.65 atm.
P
SO
2
Cl
2
=2p
o
−p
t
=2×0.5−0.65=0.35atm
Hence, rate =2.23×10
−3
×0.35
Rate =7.805×10
−4
atm/s
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