Question

0.1057 g of an oxide of the metal was quantitavely converted into 0.1827 g of its chloride. Calculate the equivalent weight of the metal
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Answer 1

USE THIS SIMPLE EQUATION

E + 8/ E+ 35.5 = 0.1057/0.1827

E+8/E+35.5 = 0.57

E + 8 = 0.57 E + 20.2

E = 28.3

             

Hope you understand

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Answer 2

Answer:

Explanation:

This is the actual answer