Math, asked by shahriesalik, 9 months ago

с
0.11. Find the area of a rhombus whose perimeter is 80cm and one of
whose diagonal is 24m.
by ( herons formula)

Answers

Answered by Anonymous
8

Step-by-step explanation:

Every Rhombus is also a Square..

In square all sides are equal

Perimeter of a square = 4s = 80/4 => s = 20cm

Area of square = 20² = 400cm²

....Area of rhombus = 400cm².

Answered by Amayrakumari
0

Answer:

Area of rhombus

Step-by-step explanation:

Perimeter=80cm

so, length of a side = 80/4 =20cm

and diagonal of a rhombus=24m

As we know that,

The halves of a diagonal and side of rhombus from a right angle triangle with side as hypotenuse.

Let the length of other diagonal =2x

x^2+(24/2)^2 =20^2=x^2+144=400

x^2=400-144=256

x=16

The measure of the another diagonal of a rhombus=2×16=32

So the area of rhombus=1/2×diagonal of a rhombus×measure of another diagonal

A= 1/2×32×24

A=348m^2

Similar questions