Question

0.115 gm of sodium was dissolved in 500 ml of the solution in dissolved water .the normality of the solution is

A) 0.010N
B) 0.0115N
C) 0.023N
D) 0.046N

Answer 1

N= wb/mb x 1000/v(ml)

Wb = 0.115g

Mb = 23 (for Sodium Molecular mass is 23)

V = 500

Applying Basic Formula

N = 0.115/23 x 1000/500

N = 115/23x500

N= 115/11500

N = 0.010