0.12 molal soll of a substance boils cet 373.210k
Calculate molal elevation constant of the solvent
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Answer:
ΔTb = Kb x m
Here ΔTb = 373.210 - 373 = 0.210
So 0.210 = Kb x 0.12
Kb = 0.21/0.12
Kb = 21/12
Kb = 1.75 K kg/mol
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