0.120kg of copper of specific heat capacity 100 cal/ kg°c and 20°C is heated by a burner for two minutes?heat energy at a rate of 20cal/sec
Calculate the final tempratureof copper
Answers
Answered by
1
m = 0.12kg
s = 100cal/kg/℃
T
1
T1 = 20℃
T
2
T2 = ?
△
△T =
T
2
−
T
1
T2−T1
Heat supplied by burner
⇒
⇒ = 20calories/sec
Time heated for = 2 minutes
⇒
⇒ = 2
×
×60
⇒
⇒ = 120 seconds.
Total heat received
⇒
⇒ = Heat per second
×
× time (in seconds)
⇒
⇒ = 120
×
×20
⇒
⇒ = 2400cal.
Q = ms
△
△T
2400 = 0.12
×
×100
×
×
△
△T
△
△T =
2400
Y
0.12
×
100
2400Y0.12×100
△
△T = 200
T
2
−
T
1
T2−T1 = 200
T
2
T2-20 = 200
T
2
T2 = 200℃.
Answered by
0
Answer:
124.5 degree Celsius its the correct answer
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