Question

0.123 3bar in the form of
p/q

Answer 1

let

x=0.12333.....

now multiply it with 100; i.e

100x= 12.333..... (equation1)

now multiply it with 10; i.e

1000x= 123.333..... (equation 2)

now, subtract equation 2 - equation 1; i.e

1000x-100x= (123.333....) - (12.333....)
900x= 121
x= 121/900 ans

Answer 2

12333...   /  100000...
as the nos go the zeroes shall also continue