Question

0.126 g of an acid requires 20ml of 0.1N NaOH for complete neutralisation. Eq wt of the acid is?

Answer 1

N = [(W/E) * 1000] / V_ml

E = [(W/N) * 1000] / V_ml
= [(0.126/0.1) * 1000] /20
= 63 g

Equivalent weight of acid (E) is 63 g

Answer 2

Answer: Equivalent weight of acid is 63 grams.

Explanation:-

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

$\text{no of gram equivalents}={\text{Normality}\times {\text{Volume in L}}$

$\text{no of gram equivalents of NaOH}={\text{0.1N}\times 0.02L=0.002gram equivalents$

As we know 1 gram equivalents of base will react with equivalent weight of acid.

0.002 gram equivalents of base is neutralized by 0.126 g of acid

1 gram equivalents of base is neutralized by =$\frac{0.126}{0.002}\times 1=63 g$ of acid.

Thus equivalent mass of acid is 63 grams.