Question

0-13.1f tan 2A=cot(A-18)where 2A is an acule angle , find the value of A​

Answer 1

Given tan2A=cot(A−18 °)

⇒cot(90−2A)=cot(A−18 °)

[∵tanθ=cot(90−θ)]

Comparing angles we get

90−2A=A−18

⇒90+18=A+2A

⇒3A=108

⇒A= 108/3

⇒A=36 °