Question

0.134(bar in 134) subtract 0.0032(bar in 32) Express the result in the form of p upon q where p and q are integers and q is not equals to zero

Answer 1

Solution for 7th question.

p/q=143848 / 1098900

Answer 2

$0.\overline{134}-0.00\overline{32}=\frac{323658}{2472525}$

Step-by-step explanation:

Given : Expression $0.\overline{134}-0.00\overline{32}$

To find : Express the result in the form of p upon q where p and q are integers and q is not equals to zero ?

Solution :

Let $x=0.134134...$ ....(1)

Multiply both side by 1000,

$1000x=134.134.134...$ .....(2)

Subtract (1) and (2),

$1000x-x=(134.134.134....)-(0.134134...)$

$999x=134$

$x=\frac{134}{999}$

Similarly,

Let $y=0.003232...$ ....(1)

Multiply both side by 100,

$100y=0.323232...$ .....(2)

Subtract (1) and (2),

$100y-y=(0.323232...)-(0.003232...)$

$99y=0.32$

$y=\frac{0.32}{99}$

$y=\frac{32}{9900}$

Now, $0.\overline{134}-0.00\overline{32}$

$x-y=\frac{134}{999}-\frac{32}{9900}$

$x-y=\frac{134\times 9900-32\times 999}{999\times 9900}$

$x-y=\frac{1326600-31968}{999\times 9900}$

$x-y=\frac{1294632}{999\times 9900}$

$x-y=\frac{323658}{2472525}$

Therefore, $0.\overline{134}-0.00\overline{32}=\frac{323658}{2472525}$

#Learn more

Represent 0.13 bar in p/q form ​

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