Question

0.14 ABCD is a quadrilateral in which AB = 32 cm, BC = 52 cm, CD = 52
cm, AD = 24 cm and angle A = 90°, diagonal BD divides the quadrilateral
in two triangles BAD and BCD. Find
(a) Which triangle has more area and how much?
(b) Total area of a quadrilateral ABCD.​

Answer 1

Answer:

1.We have:

Base = 24 cm

Height = 14.5 cm

Now,

Area of triangle=

1

2

×Base×Height=

1

2

×24

2.Let the height of the triangle be h m.

∴ Base = 3h m

Now,

Area of the triangle =

Total Cost

Rate

=

783

58

=13.5 ha =135000 m2

We have:

Area of triangle = 135000 m2⇒

1

2

×Base×Height =135000⇒

1

2

×3h×h =135000⇒h2=

135000×2

3

⇒h2=90000⇒h =300 m

Thus, we have:

Height = h = 300 m

Base = 3h = 900 m