Question

0.14 g of an element on combustion gives 0.28 g of its oxide what is an element​

Answer 1

Answer:

$\huge\underline\orange{\mathcal Answer:-}$

$\large\blue{\boxed{\mathcal Element\:is\:Sulphur}}$

$\huge\underline\green{\mathcal Solution:-}$

$\large{Equivalent\:Weight\:Of\: Element={\frac{Weight\:Of\:Element}{Weight\:Of\:Oxygen}}×8}$

$\large{= {\frac{0.14}{0.28-0.14}}×8}$

$\large{= {\frac{0.14}{0.14}}×8}$

$\large{\boxed{Equivalent\:Weight=8}}$

___________________________________

Thus element should be " sulphur "as its equivalent Weight can be 8 .

S + O2 ----> SO2

Here ,

32 g(1 mole) of Sulphur on combustion gives oxide = 64 g (32+[2×16] = 64)

Therefore ,

0.14 g of sulphur on combustion will give oxide :-

$\large{\mathcal ={\frac{64×0.14}{32}}=0.28}$

Hence , it is cleared that the element is Sulphur

$\huge\orange{\mathcal Hope\:It\:Helps}$