Question

0.144/0.24×100 in step by step please​

Answer 1

Explanation:

Total mass of compound = 0.24 g

Mass of boron in it = 0.096 g

Therefore % composition by weight of boron = (Mass of boron/ Total mass of compound)*100

= (0.096/0.24)*100

= 40 %

Mass of oxygen in the compound = 0.144 g

Therefore % composition by weight of oxygen = (Mass of oxygen/ Total mass of compound)*100

= (0.144/0.24)*100

= 60 %.

The compound is made up of only boron and oxygen, therefore the % composition of the componenets sum to 100% (60% + 40%

Answer 2

0.144/0.24×100

0.016

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