Question

0.144 gram of pure 24 10 in dilute h2 s o4 and solution for 200 ml volume in ml of 0.1 molar kmn o4 will be needed

Answer 1

Explanation:

What volume of 0.1M KMnO4 is needed to completely oxidize 100g of FeC2O4 in an acidic solution?

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Number of equivalents of both the species needs to be the same .

1 mole(144g) of FeC2O4 gives 3 moles of electrons to oxidize into Fe3+ and CO2 . So, 100 g gives 100×3144=2.0833 moles of elecrrons.

One mole of KMnO4 needs 5 moles of electrons in acidic medium to reduce to Mn2+ .

So, to take the 2.0833 moles of electrons given out by Ferrous oxalate , we need 2.085=0.4167 moles of KMnO4.

To find the volume of 0.1 M solution,which contains the required 0.4167 moles ,

V=0.41670.1=4.167L

So, you need 4.167 L of 0.1 M potassium permanganate solution to oxidize 100grams of ferrous oxalate in acidic medium.