Question

-0.: + 14y + 50 = 0
D) x2 + y2 + 6x + 14y = 0
Find the equation of a circle that has its centre on the line x = 1 - y passing
through origin & (4,2).
A x2 + y2 - 4x + 3y = 0
B) x2 + y2 + 8x - y = 0
S + y2 - 8x + 6y = 0
D) x2 + y2 - 8x - 6y = 0​

Answer 1

Answer:

please give me Bren less