Question

0.15 Determine the Change in wavelength of light during its goal
glass. IfRL of glass w.rt air is 15 and frequency of​

Answer 1

Explanation:

Given : μ

8

=1.5;n=4×10

14

Hz;c=3×10

8

m/s

The wavelength of light incident on glass from air is

x

a

=

n

c

=

4×10

14

3×10

8

=7.5×10

−7

m=7500×10

−10

=7500A

Now, the velocity of light in glass is given from its refractive index as

μ

g

=

v

g

c

We also know that velocity is product of frequency and wavelength.

∴μ

g

=

v

g

c

=

nλ

g

nλ

σ

=

λ

g

λ

σ

∴λ

g

=

λ

g

λ

σ

=

1.5

7500

=5000

A

o

Therefore, the difference in wavelength is

λ

σ

−λ

g

=7500−5000=2500

A

o

The wave number is the reciprocal of the wavelength.

Therefore, the wave number in glass is

λ

g

=

λ

g

1

∴

λ

g

=

5×10

−7

1

=2×10

6

m

−1

Answer 2

Answer:

same like up side written