Question

0.150g of an hydrocarbon on complete combustion gave 0.44g of CO2 . Tbe percentage of conposition of carbon in the hydrocarbon is

Answer 1

Answer:

percentage of composition of C in the given hydrocarbon is 80%

Explanation:

Given that,

     weight of hydrocarbon = 0.15 g

                   weight of CO₂ = 0.44 g

             atomic mass of C = 12 u

   molecular mass of CO₂ = 44 u

The formula to find the percentage of composition of C in the given compound is,

     $\% C =\frac{mass\; of\; \;C}{mass\:of\:CO_2}\times\frac{wieght \;of \;CO_2}{weight\;of\;compound} \times100$

⇒         $=\frac{12}{44}\times\frac{0.44}{0.15}\times100 =80\%$

The % C in the given hydrocarbon is 80%