0.16(5y - 2) = 0.4y + 7
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Answered by
16
0.16(5y -2) = 0.4y + 7
0.8y - 0.32 = 0.4y +7
0.8y - 0.4y = 7 + 0.32
0.4y = 7.32
y = 18.3
0.8y - 0.32 = 0.4y +7
0.8y - 0.4y = 7 + 0.32
0.4y = 7.32
y = 18.3
Answered by
6
Hey dear,
here is the answer for your question
0.8y-0.32 = 0.4y+7 (0.16 x 5y =0.8y ... 0.16 x -2= 0.32)
0.8y - 0.4y= 7+0.32
0.4y=7.32
y=7.32/0.4
y=18.3
hope it helped you
###############################################################
thankz
here is the answer for your question
0.8y-0.32 = 0.4y+7 (0.16 x 5y =0.8y ... 0.16 x -2= 0.32)
0.8y - 0.4y= 7+0.32
0.4y=7.32
y=7.32/0.4
y=18.3
hope it helped you
###############################################################
thankz
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