0.16 g sample of a compound of carbon and hydrogen was found by analysis to contain 0.04 g of
hydrogen and 0.12 g of Carbon. Calculate the percentage composition of the compound by weight.
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Explanation:
Moles of C= moles of CO
2
=
44
0.44
=0.01 moles
Moles of H=2×moles of H
2
O=2×
18
0.18
=0.02 moles
Weight of oxygen = ( 0.30 - weight of carbon and hydrogen ) = (0.3−0.01×12−0.02×1)=0.16 gm
Moles of O=
16
0.16
=0.01 moles
Empirical formula =CH
2
O
Empirical formula mass =30 gm
n=
30
60
=2
Formula=(CH
2
O)
n
=C
2
H
4
O
2
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