Question

0.17 g of ammonia on decomposition gave 0.l4 g of nitrogen and rest hydrogen.what will be the volume of hydrogen evolved at S.T.P?

Answer 1

Hello Dear.

Here is the answer---

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Mass of Ammonia = 0.17 grams.
Mass of Nitrogen Produced = 0.14 grams.

Reaction of the Decomposition of the Ammonia will be---

                    2NH₃ ----------------------------- N₂ + 3H₂


Now,
Molecular Mass of Ammonia = 17 grams
Molecular Mass of Nitrogen = 28 grams
Molecular Mass of Hydrogen = 2 grams.

From the Reaction,

 ∵ 34 grams of the ammonia produces 3 × 3 grams of H₂.
 ∴ 1 grams--------------------------------------9/34 grams of H₂.
 ∴ 0.17 grams----------------------------------(9/34) × 0.17 g of H₂.
                                                               = 0.045 grams.


Now, We know, 2 grams of Hydrogen occupies the volume of 22.4 liter at S.T.P.



Thus, 1 grams of H₂ Occupies the Volume of 22.4/2 Liter.

∴ 0.045 grams---------------------------11.2 × 0.045 liter.
                                                          = 0.504 liter.

Thus, the volume occupied by the Hydrogen which is evolved during the Decomposition of Ammonia is 0.504 liter.


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Hope it helps.

Have a Marvelous Day.