Question

(0)
-
+
18. ſx tan’x dx HT
(a) x tan x + log cos x + c
x²
(b) x tan x + log cos x + - +
2
x2
(c) x tanx + log cosx+c
2
(d) उपरोक्त में से कोई नहीं
4.5$​

Answer 1

Answer:

ANSWER

Let say

I=∫e  

x

[tanx−log(cosx)]dx

I=∫e  

x

[tanx+log(cosx)  

−1

]dx

I=∫e  

x

[logsecx+tanx]dx

Now if I check differentiation of 'logsecx' then -  

=  

secx

1

​  

×secxtanx=tanx

So, given integral is in the form also -  

∫e  

x

(f(x  

+

​  

f  

′

(x)dx=e  

x

f(x)+C

So, I=e  

x

log(secx)+C

option A

Step-by-step explanation:

Answer 2

Answer:

option A is the correct answer buddy