Question

0.19. Find that value(s) of x for which the distance between the points P(x, 4) and Q(9, 10) is 10 units​

Answer 1

$\huge\boxed{\fcolorbox{cyan}{grey}{Solution:-}}$.

➡Given here.

↪Distance between two point.

=>10 = √ [(x-9)²+(4-10)²].

=>10 = √[ (x-9)²+(-6)²]

=> 100=(x-9)²+36

=>x²+81-18x+36=100.

=>x²-18x117-100=0.

=>x²-18x+17=0.

=>x²-17x-x+17=0.

=>x(x-17)-1(x-17)=0.

=>(x-17)(x-1)=0.

=>x-17=0 or x-1=0.

=>x= 17. or x= 1.

➡Thus:-

♠Value of x= 17, 1.

➡Hopes its helpa u.

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