Question

0.1914 g of organic acid is dissolved in 20 ml of water. 25 ml of 0.12 N NaOH is required forcomplete neutralisation of the acid solution. The equivalent weight of the acid is

Answer 1

I don't know what is the answer

Answer 2

From law of chemical equivalence,

no. of gm eq. of acid =no. of gm eq. of NaOH

(0.1914/x)=25*(0.12)*(10^-3)

x=0.0319(10^3)

so x=31.9

here x is eq. mass of acid

In above, 10^-3 is multiplied because volume is in ml and to convert it to litre we did that as N*V(in ml)*10^-3 =no. gm eq.