[0.1A current is flowing through a 100 ohm resistor for 2 minutes. a. Calculate the heat released. b.Calculate the power.]
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Answered by
9
Answer:
a) heat released =120 J
b)power =1 watt
Explanation:
a) I= 0.1A ,. r=100 ohm,. t=2mins=120sec
according to Joule law of heating
w=I^2Rt
=0.1*0.1*100*120
=120J
b) power is the rate at which work is done.
p=w/t
= I^2Rt/t
=120/120=1
therefore,power=1 watt
Answered by
0
POWER IS 1 WATT & HEAT RELEASED IS 120 JOULES.
Given:
- Resistance = 100 ohm
- Time = 2 min = 2 × 60 = 120 sec
- Current = 0.1 Ampere
To find:
- Heat released & Power ?
Calculation:
The general expression of heat released in a circuit is given as :
- i is current, r is resistance and t is time.
Now, power dissipated in circuit is :
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