Question

0.1A current is flowing through a 100 ohm resistor for 2 minutes. a. Calculate the heat released. b.Calculate the power.]

Answer 1

Answer:

0.1A current is flowing through a 100 ohm resistor for 2 minutes. a. Calculate the heat released. b.Calculate the power.]

Answer 2

Answer:

heat released is 120J

power 1 watt

Explanation:

a) I=0.1A, r=100 ohm, t=2 mins=120sec

according to the Joule law of heating

w=I^2Rt

= 0.1*0.1*100*120

=120J

b) power is the rate at which work is done.

p=w/t

I^2Rt/t

=120/120=1

therefore,power=1 watt