Question

0.1g of a solution containing na2co3 and nahco3 requires 10 ml of 0.01 n hcl for neutralization using phenolphthalein as an indicator. Wt. % of na2co3 is :

Answer 1

Answer:

Explanation:

equivalent of na2co3 = equivalent of hcl

equivalent of na2co3 = 0.1

moles*f*1000 = 0.1

moles = 0.0001

w/100 = 0.0001

w=0.01

weight percentage = 0.01/0.1 *100

=10