0.1gram of metal gave on treatment with a dilute acid 34.2ml of hydrogen at stp.calculate equivalent weight of the metal
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Moles at STP => V/22.4 => 34.2/22400 = > 1.526 millimoles.
Eq. weight = 0.1/ 1.526 x 10^-3 => 65.5307 gm
sorry for late giving answer
Moles at STP => V/22.4 => 34.2/22400 = > 1.526 millimoles.
Eq. weight = 0.1/ 1.526 x 10^-3 => 65.5307 gm
sorry for late giving answer
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Answered by
2
Answer:
Eq. wt = Wt. of metal/V. of H2 displaced at STP ×11200
=0.1/34.2×11200
=32.7
The answer is 32.7
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