Question

0.1M NaOH is titrated with 0.1 M HA till the end point, Ka for HA is 5.6 x 10^-6 and degree of hydrolysis is less compared to 1. Calculate pH of the resulting solution at the end point.
[JEE-2004]


Please help.
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Answer 1

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$11 {yy22}^{332}$

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$221.x2 = 6 \times \frac{?}{?}$